// Dick 	cs201/lab/05		Illogical.cc
// Date:	 Mon May  1 06:28:10 PDT 1995
// WARNING:  This has bugs... find them
//		also I don't use this in my grading ...

/* 
-------------Problem------------
To convert letter grades into per centage scores according to rules
in the syllabus... using middle of ranges.
-------------Analysis-----------

DATA REQUIREMENTS
  Constants
	a,b,c,d,f	(int) values of grades 'a', 'b', ...	
  Inputs
	grade (char)
  Outputs
	percent (int)	
FORMULAE
	see cs201/syllabus
		a=100%, b=85%, c=75%, d=65%, f=30%
--------------Design-------------

INITIAL ALGORITHM
	1, read the grade
	2. convert to percent
	3. display percent

REFINEMENTS
	2. To convert to percent
		2.1 if grade is 'A' then percent is a
		2.2 if grade is 'B' then percent is b
		2.3 if grade is 'C' then percent is c
		2.4 if grade is 'D' then percent is d
		2.5 else percent is e.

------------Implementation---------
*/

#include <iostream.h>

int main( )
{ 
	const int a =100;
	const int b = 85;
	const int c = 75;
	const int d = 65;
	const int f = 30;
	char grade;	
	int percent;

	cout << "Input the grade> ";
	cin >> grade;

	if(grade = 'A')
		percent = a;
	else if(grade == 'B')
		percent = b;
	else if(grade == 'C')
		percent = c;
	else if(grade == 'D')
		percent = d;
	else
		percent = f;

	cout << percent <<"%";
  return 0; // terminate program with an "all ok" result returned to UNIX
}